Project Euler – 1

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.

int Problem1() {
	int current = 0;
	int result  = 0;
	while ( current < 1000 ) {
		if ( current % 5 == 0 || current % 3 == 0 ) {
			result += current;
		}
		current++;
	}
	return result;
}
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