If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

int Problem1() {
int current = 0;
int result = 0;
while ( current < 1000 ) {
if ( current % 5 == 0 || current % 3 == 0 ) {
result += current;
}
current++;
}
return result;
}

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